3x^2+12x=3(x^2+4x)

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Solution for 3x^2+12x=3(x^2+4x) equation:


Simplifying
3x2 + 12x = 3(x2 + 4x)

Reorder the terms:
12x + 3x2 = 3(x2 + 4x)

Reorder the terms:
12x + 3x2 = 3(4x + x2)
12x + 3x2 = (4x * 3 + x2 * 3)
12x + 3x2 = (12x + 3x2)

Add '-12x' to each side of the equation.
12x + -12x + 3x2 = 12x + -12x + 3x2

Combine like terms: 12x + -12x = 0
0 + 3x2 = 12x + -12x + 3x2
3x2 = 12x + -12x + 3x2

Combine like terms: 12x + -12x = 0
3x2 = 0 + 3x2
3x2 = 3x2

Add '-3x2' to each side of the equation.
3x2 + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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